0=16t^2+50t+15

Solution for 0=16t^2+50t+15 equation:

0=16t^2+50t+15

We move all terms to the left:

0-(16t^2+50t+15)=0

We add all the numbers together, and all the variables

-(16t^2+50t+15)=0

We get rid of parentheses

-16t^2-50t-15=0

a = -16; b = -50; c = -15;
Δ = b2-4ac
Δ = -502-4·(-16)·(-15)
Δ = 1540
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1540}=\sqrt{4*385}=\sqrt{4}*\sqrt{385}=2\sqrt{385}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-2\sqrt{385}}{2*-16}=\frac{50-2\sqrt{385}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+2\sqrt{385}}{2*-16}=\frac{50+2\sqrt{385}}{-32}
$